Base | Representation |
---|---|
bin | 11010001010000011101001… |
… | …001100001100110000111010 |
3 | 120002022202011102222110100010 |
4 | 122022003221030030300322 |
5 | 110034310031441023102 |
6 | 1044400443003322350 |
7 | 33142250165540430 |
oct | 3212035114146072 |
9 | 502282142873303 |
10 | 115040316345402 |
11 | 33723362533778 |
12 | 10a9b7012203b6 |
13 | 4c26341b198b6 |
14 | 2059da3cc0d50 |
15 | d476e15a7d6c |
hex | 68a0e930cc3a |
115040316345402 has 64 divisors (see below), whose sum is σ = 263683005721344. Its totient is φ = 32776967139840.
The previous prime is 115040316345391. The next prime is 115040316345413. The reversal of 115040316345402 is 204543613040511.
It is an interprime number because it is at equal distance from previous prime (115040316345391) and next prime (115040316345413).
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 144937702 + ... + 145729262.
It is an arithmetic number, because the mean of its divisors is an integer number (4120046964396).
Almost surely, 2115040316345402 is an apocalyptic number.
115040316345402 is an abundant number, since it is smaller than the sum of its proper divisors (148642689375942).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
115040316345402 is a wasteful number, since it uses less digits than its factorization.
115040316345402 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 801223.
The product of its (nonzero) digits is 172800, while the sum is 39.
Adding to 115040316345402 its reverse (204543613040511), we get a palindrome (319583929385913).
The spelling of 115040316345402 in words is "one hundred fifteen trillion, forty billion, three hundred sixteen million, three hundred forty-five thousand, four hundred two".
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