1150443341 has 4 divisors (see below), whose sum is σ = 1153578432. Its totient is φ = 1147308252.

The previous prime is 1150443337. The next prime is 1150443353. The reversal of 1150443341 is 1433440511.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 1433440511 = 3217 ⋅445583.

It is a cyclic number.

It is not a de Polignac number, because 1150443341 - 2² = 1150443337 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a self number, because there is not a number n which added to its sum of digits gives 1150443341.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1150443241) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1566995 + ... + 1567728.

It is an arithmetic number, because the mean of its divisors is an integer number (288394608).

Almost surely, 2^1150443341 is an apocalyptic number.

It is an amenable number.

1150443341 is a deficient number, since it is larger than the sum of its proper divisors (3135091).

1150443341 is an equidigital number, since it uses as much as digits as its factorization.

1150443341 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3135090.

The product of its (nonzero) digits is 2880, while the sum is 26.

The square root of 1150443341 is about 33918.1859921783. The cubic root of 1150443341 is about 1047.8241688408.

Adding to 1150443341 its reverse (1433440511), we get a palindrome (2583883852).

It can be divided in two parts, 11504 and 43341, that added together give a palindrome (54845).

The spelling of 1150443341 in words is "one billion, one hundred fifty million, four hundred forty-three thousand, three hundred forty-one".