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1150443433 is a prime number
BaseRepresentation
bin100010010010010…
…0101111110101001
32222011202120201001
41010210211332221
54324003142213
6310053555001
740336415326
oct10444457651
92864676631
101150443433
115404391a7
12281345a61
13154462b79
14acb0db4d
156aeec1dd
hex44925fa9

1150443433 has 2 divisors, whose sum is σ = 1150443434. Its totient is φ = 1150443432.

The previous prime is 1150443409. The next prime is 1150443439. The reversal of 1150443433 is 3343440511.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 610485264 + 539958169 = 24708^2 + 23237^2 .

It is an emirp because it is prime and its reverse (3343440511) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1150443433 is a prime.

It is not a weakly prime, because it can be changed into another prime (1150443439) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 575221716 + 575221717.

It is an arithmetic number, because the mean of its divisors is an integer number (575221717).

Almost surely, 21150443433 is an apocalyptic number.

It is an amenable number.

1150443433 is a deficient number, since it is larger than the sum of its proper divisors (1).

1150443433 is an equidigital number, since it uses as much as digits as its factorization.

1150443433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 8640, while the sum is 28.

The square root of 1150443433 is about 33918.1873483829. The cubic root of 1150443433 is about 1047.8241967720.

Adding to 1150443433 its reverse (3343440511), we get a palindrome (4493883944).

The spelling of 1150443433 in words is "one billion, one hundred fifty million, four hundred forty-three thousand, four hundred thirty-three".