Base | Representation |
---|---|
bin | 110101100100101101… |
… | …1011001010100100001 |
3 | 101222221221010222100212 |
4 | 1223021123121110201 |
5 | 3341104412123323 |
6 | 124504053423505 |
7 | 11212003361054 |
oct | 1531133312441 |
9 | 358857128325 |
10 | 115048551713 |
11 | 448789a97a7 |
12 | 1a36963ab95 |
13 | ab06427904 |
14 | 57d58c2a9b |
15 | 2ed543eb78 |
hex | 1ac96d9521 |
115048551713 has 2 divisors, whose sum is σ = 115048551714. Its totient is φ = 115048551712.
The previous prime is 115048551679. The next prime is 115048551763. The reversal of 115048551713 is 317155840511.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 77850486289 + 37198065424 = 279017^2 + 192868^2 .
It is a cyclic number.
It is not a de Polignac number, because 115048551713 - 26 = 115048551649 is a prime.
It is not a weakly prime, because it can be changed into another prime (115048551763) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57524275856 + 57524275857.
It is an arithmetic number, because the mean of its divisors is an integer number (57524275857).
Almost surely, 2115048551713 is an apocalyptic number.
It is an amenable number.
115048551713 is a deficient number, since it is larger than the sum of its proper divisors (1).
115048551713 is an equidigital number, since it uses as much as digits as its factorization.
115048551713 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 84000, while the sum is 41.
The spelling of 115048551713 in words is "one hundred fifteen billion, forty-eight million, five hundred fifty-one thousand, seven hundred thirteen".
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