Base | Representation |
---|---|
bin | 11010001010001100101010… |
… | …101100000011100111000011 |
3 | 120002100200011200011201211022 |
4 | 122022030222230003213003 |
5 | 110034434402304301042 |
6 | 1044405124232140055 |
7 | 33143042244164534 |
oct | 3212145254034703 |
9 | 502320150151738 |
10 | 115050005150147 |
11 | 33727484618121 |
12 | 10aa1565b3762b |
13 | 4c272271b9662 |
14 | 205a64299868b |
15 | d47aabe94cd2 |
hex | 68a32ab039c3 |
115050005150147 has 2 divisors, whose sum is σ = 115050005150148. Its totient is φ = 115050005150146.
The previous prime is 115050005150099. The next prime is 115050005150173. The reversal of 115050005150147 is 741051500050511.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 115050005150147 - 236 = 114981285673411 is a prime.
It is not a weakly prime, because it can be changed into another prime (115050005155147) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57525002575073 + 57525002575074.
It is an arithmetic number, because the mean of its divisors is an integer number (57525002575074).
Almost surely, 2115050005150147 is an apocalyptic number.
115050005150147 is a deficient number, since it is larger than the sum of its proper divisors (1).
115050005150147 is an equidigital number, since it uses as much as digits as its factorization.
115050005150147 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 17500, while the sum is 35.
The spelling of 115050005150147 in words is "one hundred fifteen trillion, fifty billion, five million, one hundred fifty thousand, one hundred forty-seven".
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