Base | Representation |
---|---|
bin | 110101100100110110… |
… | …1100001110100101011 |
3 | 101222222021002110211101 |
4 | 1223021231201310223 |
5 | 3341112121231011 |
6 | 124504343342231 |
7 | 11212061646322 |
oct | 1531155416453 |
9 | 358867073741 |
10 | 115053305131 |
11 | 44880656046 |
12 | 1a36b151977 |
13 | ab0740039b |
14 | 57d639d0b9 |
15 | 2ed5a7d2c1 |
hex | 1ac9b61d2b |
115053305131 has 2 divisors, whose sum is σ = 115053305132. Its totient is φ = 115053305130.
The previous prime is 115053305089. The next prime is 115053305153. The reversal of 115053305131 is 131503350511.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 115053305131 - 217 = 115053174059 is a prime.
It is a super-2 number, since 2×1150533051312 (a number of 23 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 115053305131.
It is not a weakly prime, because it can be changed into another prime (115053305431) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57526652565 + 57526652566.
It is an arithmetic number, because the mean of its divisors is an integer number (57526652566).
Almost surely, 2115053305131 is an apocalyptic number.
115053305131 is a deficient number, since it is larger than the sum of its proper divisors (1).
115053305131 is an equidigital number, since it uses as much as digits as its factorization.
115053305131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3375, while the sum is 28.
Adding to 115053305131 its reverse (131503350511), we get a palindrome (246556655642).
The spelling of 115053305131 in words is "one hundred fifteen billion, fifty-three million, three hundred five thousand, one hundred thirty-one".
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