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11505401396353 is a prime number
BaseRepresentation
bin1010011101101100111101…
…0111001111110010000001
31111201220110012112202101201
42213123033113033302001
53002001030224140403
640245301453301201
72265144400156144
oct247331727176201
944656405482351
1011505401396353
113736460163437
1213599a7794801
13655c54610737
142bac15ca605b
1514e4365d121d
hexa76cf5cfc81

11505401396353 has 2 divisors, whose sum is σ = 11505401396354. Its totient is φ = 11505401396352.

The previous prime is 11505401396317. The next prime is 11505401396371. The reversal of 11505401396353 is 35369310450511.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11239075215729 + 266326180624 = 3352473^2 + 516068^2 .

It is a cyclic number.

It is not a de Polignac number, because 11505401396353 - 213 = 11505401388161 is a prime.

It is a super-2 number, since 2×115054013963532 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (11505401396303) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5752700698176 + 5752700698177.

It is an arithmetic number, because the mean of its divisors is an integer number (5752700698177).

Almost surely, 211505401396353 is an apocalyptic number.

It is an amenable number.

11505401396353 is a deficient number, since it is larger than the sum of its proper divisors (1).

11505401396353 is an equidigital number, since it uses as much as digits as its factorization.

11505401396353 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 729000, while the sum is 46.

The spelling of 11505401396353 in words is "eleven trillion, five hundred five billion, four hundred one million, three hundred ninety-six thousand, three hundred fifty-three".