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115105365531131 is a prime number
BaseRepresentation
bin11010001011000000001110…
…011011001001100111111011
3120002112222001211111110210012
4122023000032123021213323
5110041341242033444011
61044450401441212135
733150042155516303
oct3213001633114773
9502488054443705
10115105365531131
1133748a030627a8
1210ab023603104b
134c2c50a667241
14205d1b519a603
15d4924c22aa8b
hex68b00e6c99fb

115105365531131 has 2 divisors, whose sum is σ = 115105365531132. Its totient is φ = 115105365531130.

The previous prime is 115105365531113. The next prime is 115105365531151. The reversal of 115105365531131 is 131135563501511.

Together with previous prime (115105365531113) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 115105365531131 - 218 = 115105365268987 is a prime.

It is a super-2 number, since 2×1151053655311312 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (115105365531151) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57552682765565 + 57552682765566.

It is an arithmetic number, because the mean of its divisors is an integer number (57552682765566).

Almost surely, 2115105365531131 is an apocalyptic number.

115105365531131 is a deficient number, since it is larger than the sum of its proper divisors (1).

115105365531131 is an equidigital number, since it uses as much as digits as its factorization.

115105365531131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 101250, while the sum is 41.

The spelling of 115105365531131 in words is "one hundred fifteen trillion, one hundred five billion, three hundred sixty-five million, five hundred thirty-one thousand, one hundred thirty-one".