Base | Representation |
---|---|
bin | 11010001011000000001110… |
… | …011011001001100111111011 |
3 | 120002112222001211111110210012 |
4 | 122023000032123021213323 |
5 | 110041341242033444011 |
6 | 1044450401441212135 |
7 | 33150042155516303 |
oct | 3213001633114773 |
9 | 502488054443705 |
10 | 115105365531131 |
11 | 33748a030627a8 |
12 | 10ab023603104b |
13 | 4c2c50a667241 |
14 | 205d1b519a603 |
15 | d4924c22aa8b |
hex | 68b00e6c99fb |
115105365531131 has 2 divisors, whose sum is σ = 115105365531132. Its totient is φ = 115105365531130.
The previous prime is 115105365531113. The next prime is 115105365531151. The reversal of 115105365531131 is 131135563501511.
Together with previous prime (115105365531113) it forms an Ormiston pair, because they use the same digits, order apart.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 115105365531131 - 218 = 115105365268987 is a prime.
It is a super-2 number, since 2×1151053655311312 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (115105365531151) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57552682765565 + 57552682765566.
It is an arithmetic number, because the mean of its divisors is an integer number (57552682765566).
Almost surely, 2115105365531131 is an apocalyptic number.
115105365531131 is a deficient number, since it is larger than the sum of its proper divisors (1).
115105365531131 is an equidigital number, since it uses as much as digits as its factorization.
115105365531131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 101250, while the sum is 41.
The spelling of 115105365531131 in words is "one hundred fifteen trillion, one hundred five billion, three hundred sixty-five million, five hundred thirty-one thousand, one hundred thirty-one".
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