115105433 has 2 divisors, whose sum is σ = 115105434. Its totient is φ = 115105432.

The previous prime is 115105427. The next prime is 115105447. The reversal of 115105433 is 334501511.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 69839449 + 45265984 = 8357^2 + 6728^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-115105433 is a prime.

It is a super-2 number, since 2×115105433² = 26498521412234978, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 115105399 and 115105408.

It is not a weakly prime, because it can be changed into another prime (115105423) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57552716 + 57552717.

It is an arithmetic number, because the mean of its divisors is an integer number (57552717).

Almost surely, 2^115105433 is an apocalyptic number.

It is an amenable number.

115105433 is a deficient number, since it is larger than the sum of its proper divisors (1).

115105433 is an equidigital number, since it uses as much as digits as its factorization.

115105433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 900, while the sum is 23.

The square root of 115105433 is about 10728.7200075312. The cubic root of 115105433 is about 486.4429806982.

Adding to 115105433 its reverse (334501511), we get a palindrome (449606944).

The spelling of 115105433 in words is "one hundred fifteen million, one hundred five thousand, four hundred thirty-three".