Base | Representation |
---|---|
bin | 1010011110000000001001… |
… | …0111101111111001011101 |
3 | 1111202101202011120022001120 |
4 | 2213200002113233321131 |
5 | 3002042102321230323 |
6 | 40251512531401153 |
7 | 2265416132542530 |
oct | 247400227577135 |
9 | 44671664508046 |
10 | 11510552133213 |
11 | 3738663666261 |
12 | 135a9a47531b9 |
13 | 656595768723 |
14 | 2bb183da4a17 |
15 | 14e6388b05e3 |
hex | a78025efe5d |
11510552133213 has 32 divisors (see below), whose sum is σ = 18515943936000. Its totient is φ = 6213421607616.
The previous prime is 11510552133193. The next prime is 11510552133253. The reversal of 11510552133213 is 31233125501511.
It is not a de Polignac number, because 11510552133213 - 214 = 11510552116829 is a prime.
It is a super-2 number, since 2×115105521332132 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11510552133253) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 41190981 + ... + 41469482.
It is an arithmetic number, because the mean of its divisors is an integer number (578623248000).
Almost surely, 211510552133213 is an apocalyptic number.
It is an amenable number.
11510552133213 is a deficient number, since it is larger than the sum of its proper divisors (7005391802787).
11510552133213 is a wasteful number, since it uses less digits than its factorization.
11510552133213 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 82660841.
The product of its (nonzero) digits is 13500, while the sum is 33.
Adding to 11510552133213 its reverse (31233125501511), we get a palindrome (42743677634724).
The spelling of 11510552133213 in words is "eleven trillion, five hundred ten billion, five hundred fifty-two million, one hundred thirty-three thousand, two hundred thirteen".
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