Base | Representation |
---|---|
bin | 110101100110100110… |
… | …1111101111001001001 |
3 | 102000010100210121120222 |
4 | 1223031031331321021 |
5 | 3341222201442421 |
6 | 124514244355425 |
7 | 11213405022521 |
oct | 1531515757111 |
9 | 360110717528 |
10 | 115112140361 |
11 | 449008908a9 |
12 | 1a3869a5b75 |
13 | ab1666012a |
14 | 5800116681 |
15 | 2edad00cab |
hex | 1acd37de49 |
115112140361 has 2 divisors, whose sum is σ = 115112140362. Its totient is φ = 115112140360.
The previous prime is 115112140327. The next prime is 115112140391. The reversal of 115112140361 is 163041211511.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 113919750400 + 1192389961 = 337520^2 + 34531^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-115112140361 is a prime.
It is a Sophie Germain prime.
It is a Curzon number.
It is a self number, because there is not a number n which added to its sum of digits gives 115112140361.
It is not a weakly prime, because it can be changed into another prime (115112140301) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57556070180 + 57556070181.
It is an arithmetic number, because the mean of its divisors is an integer number (57556070181).
Almost surely, 2115112140361 is an apocalyptic number.
It is an amenable number.
115112140361 is a deficient number, since it is larger than the sum of its proper divisors (1).
115112140361 is an equidigital number, since it uses as much as digits as its factorization.
115112140361 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 720, while the sum is 26.
Adding to 115112140361 its reverse (163041211511), we get a palindrome (278153351872).
The spelling of 115112140361 in words is "one hundred fifteen billion, one hundred twelve million, one hundred forty thousand, three hundred sixty-one".
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