11511445034 has 4 divisors (see below), whose sum is σ = 17267167554. Its totient is φ = 5755722516.

The previous prime is 11511445021. The next prime is 11511445037. The reversal of 11511445034 is 43054411511.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 43054411511 = 53 ⋅812347387.

It can be written as a sum of positive squares in only one way, i.e., 11076931009 + 434514025 = 105247^2 + 20845^2 .

It is a super-2 number, since 2×11511445034² (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 11511444988 and 11511445006.

It is not an unprimeable number, because it can be changed into a prime (11511445037) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2877861257 + ... + 2877861260.

Almost surely, 2^11511445034 is an apocalyptic number.

11511445034 is a deficient number, since it is larger than the sum of its proper divisors (5755722520).

11511445034 is an equidigital number, since it uses as much as digits as its factorization.

11511445034 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5755722519.

The product of its (nonzero) digits is 4800, while the sum is 29.

Adding to 11511445034 its reverse (43054411511), we get a palindrome (54565856545).

The spelling of 11511445034 in words is "eleven billion, five hundred eleven million, four hundred forty-five thousand, thirty-four".