Base | Representation |
---|---|
bin | 10101011100010010… |
… | …01000101100000001 |
3 | 1002201021001002120101 |
4 | 22232021020230001 |
5 | 142033430040212 |
6 | 5142140442401 |
7 | 555160455106 |
oct | 125611105401 |
9 | 32637032511 |
10 | 11511565057 |
11 | 4977a84233 |
12 | 2293249401 |
13 | 1115bcb775 |
14 | 7b2bd6aad |
15 | 47593e157 |
hex | 2ae248b01 |
11511565057 has 2 divisors, whose sum is σ = 11511565058. Its totient is φ = 11511565056.
The previous prime is 11511565007. The next prime is 11511565061. The reversal of 11511565057 is 75056511511.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 11413930896 + 97634161 = 106836^2 + 9881^2 .
It is a cyclic number.
It is not a de Polignac number, because 11511565057 - 211 = 11511563009 is a prime.
It is a super-2 number, since 2×115115650572 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (11511565007) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5755782528 + 5755782529.
It is an arithmetic number, because the mean of its divisors is an integer number (5755782529).
Almost surely, 211511565057 is an apocalyptic number.
It is an amenable number.
11511565057 is a deficient number, since it is larger than the sum of its proper divisors (1).
11511565057 is an equidigital number, since it uses as much as digits as its factorization.
11511565057 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 26250, while the sum is 37.
The spelling of 11511565057 in words is "eleven billion, five hundred eleven million, five hundred sixty-five thousand, fifty-seven".
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