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11512345040354 = 217321332323337
BaseRepresentation
bin1010011110000110110100…
…1111001001010111100010
31111202120101010020102021202
42213201231033021113202
53002104240312242404
640252410455521202
72265511433156204
oct247415517112742
944676333212252
1011512345040354
1137393a37159a4
12135b205089202
136567c0044222
142bb2b4152774
1514e6e0eb721e
hexa786d3c95e2

11512345040354 has 8 divisors (see below), whose sum is σ = 17269514582508. Its totient is φ = 5755840179520.

The previous prime is 11512345040347. The next prime is 11512345040389. The reversal of 11512345040354 is 45304054321511.

It can be written as a sum of positive squares in 2 ways, for example, as 10701763536025 + 810581504329 = 3271355^2 + 900323^2 .

It is a sphenic number, since it is the product of 3 distinct primes.

It is a Curzon number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 166127027 + ... + 166196310.

Almost surely, 211512345040354 is an apocalyptic number.

11512345040354 is a deficient number, since it is larger than the sum of its proper divisors (5757169542154).

11512345040354 is a wasteful number, since it uses less digits than its factorization.

11512345040354 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 332340660.

The product of its (nonzero) digits is 144000, while the sum is 38.

Adding to 11512345040354 its reverse (45304054321511), we get a palindrome (56816399361865).

The spelling of 11512345040354 in words is "eleven trillion, five hundred twelve billion, three hundred forty-five million, forty thousand, three hundred fifty-four".

Divisors: 1 2 17321 34642 332323337 664646674 5756172520177 11512345040354