Base | Representation |
---|---|
bin | 1010011110000111100101… |
… | …1110010001011101000111 |
3 | 1111202120220102112022210121 |
4 | 2213201321132101131013 |
5 | 3002110200341112411 |
6 | 40252443112002411 |
7 | 2265516505133614 |
oct | 247417136213507 |
9 | 44676812468717 |
10 | 11512550332231 |
11 | 3739499592803 |
12 | 135b261990407 |
13 | 656823732100 |
14 | 2bb2d351150b |
15 | 14e704019571 |
hex | a7879791747 |
11512550332231 has 12 divisors (see below), whose sum is σ = 12517979960640. Its totient is φ = 10582874190720.
The previous prime is 11512550332229. The next prime is 11512550332249. The reversal of 11512550332231 is 13223305521511.
It is not a de Polignac number, because 11512550332231 - 21 = 11512550332229 is a prime.
It is a super-2 number, since 2×115125503322312 (a number of 27 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11512550332211) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 141290391 + ... + 141371848.
It is an arithmetic number, because the mean of its divisors is an integer number (1043164996720).
Almost surely, 211512550332231 is an apocalyptic number.
11512550332231 is a deficient number, since it is larger than the sum of its proper divisors (1005429628409).
11512550332231 is a wasteful number, since it uses less digits than its factorization.
11512550332231 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 282662506 (or 282662493 counting only the distinct ones).
The product of its (nonzero) digits is 27000, while the sum is 34.
Adding to 11512550332231 its reverse (13223305521511), we get a palindrome (24735855853742).
The spelling of 11512550332231 in words is "eleven trillion, five hundred twelve billion, five hundred fifty million, three hundred thirty-two thousand, two hundred thirty-one".
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