Base | Representation |
---|---|
bin | 10101011100011101… |
… | …01101001100101011 |
3 | 1002201100210021200022 |
4 | 22232032231030223 |
5 | 142034313302243 |
6 | 5142232031055 |
7 | 555206046332 |
oct | 125616551453 |
9 | 32640707608 |
10 | 11513025323 |
11 | 4978891368 |
12 | 229383248b |
13 | 11162c0327 |
14 | 7b3096d19 |
15 | 475b2bb68 |
hex | 2ae3ad32b |
11513025323 has 2 divisors, whose sum is σ = 11513025324. Its totient is φ = 11513025322.
The previous prime is 11513025313. The next prime is 11513025343. The reversal of 11513025323 is 32352031511.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11513025323 - 218 = 11512763179 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 11513025292 and 11513025301.
It is not a weakly prime, because it can be changed into another prime (11513025313) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5756512661 + 5756512662.
It is an arithmetic number, because the mean of its divisors is an integer number (5756512662).
Almost surely, 211513025323 is an apocalyptic number.
11513025323 is a deficient number, since it is larger than the sum of its proper divisors (1).
11513025323 is an equidigital number, since it uses as much as digits as its factorization.
11513025323 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2700, while the sum is 26.
Adding to 11513025323 its reverse (32352031511), we get a palindrome (43865056834).
The spelling of 11513025323 in words is "eleven billion, five hundred thirteen million, twenty-five thousand, three hundred twenty-three".
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