11513060614141 has 4 divisors (see below), whose sum is σ = 12119011172800. Its totient is φ = 10907110055484.

The previous prime is 11513060614123. The next prime is 11513060614207. The reversal of 11513060614141 is 14141606031511.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 11513060614141 - 2⁵ = 11513060614109 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11513060614097 and 11513060614106.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11513060614841) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 302975279301 + ... + 302975279338.

It is an arithmetic number, because the mean of its divisors is an integer number (3029752793200).

Almost surely, 2^{11513060614141} is an apocalyptic number.

It is an amenable number.

11513060614141 is a deficient number, since it is larger than the sum of its proper divisors (605950558659).

11513060614141 is an equidigital number, since it uses as much as digits as its factorization.

11513060614141 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 605950558658.

The product of its (nonzero) digits is 8640, while the sum is 34.

Adding to 11513060614141 its reverse (14141606031511), we get a palindrome (25654666645652).

The spelling of 11513060614141 in words is "eleven trillion, five hundred thirteen billion, sixty million, six hundred fourteen thousand, one hundred forty-one".