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115130632662049 is a prime number
BaseRepresentation
bin11010001011010111110000…
…011101100110110000100001
3120002122101021202001201022211
4122023113300131212300201
5110042300013430141144
61044510141003402121
733151625255552104
oct3213276035466041
9502571252051284
10115130632662049
1133758699763184
1210ab5107b23341
134c31a06330694
1420604d0bdc73b
15d49c2a5b8034
hex68b5f0766c21

115130632662049 has 2 divisors, whose sum is σ = 115130632662050. Its totient is φ = 115130632662048.

The previous prime is 115130632661963. The next prime is 115130632662083. The reversal of 115130632662049 is 940266236031511.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 78612481511424 + 36518151150625 = 8866368^2 + 6043025^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-115130632662049 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 115130632661993 and 115130632662011.

It is not a weakly prime, because it can be changed into another prime (115130632362049) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57565316331024 + 57565316331025.

It is an arithmetic number, because the mean of its divisors is an integer number (57565316331025).

Almost surely, 2115130632662049 is an apocalyptic number.

It is an amenable number.

115130632662049 is a deficient number, since it is larger than the sum of its proper divisors (1).

115130632662049 is an equidigital number, since it uses as much as digits as its factorization.

115130632662049 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1399680, while the sum is 49.

The spelling of 115130632662049 in words is "one hundred fifteen trillion, one hundred thirty billion, six hundred thirty-two million, six hundred sixty-two thousand, forty-nine".