Base | Representation |
---|---|
bin | 11010001011011001010101… |
… | …001011101100000100000101 |
3 | 120002122112122111201112211110 |
4 | 122023121111023230010011 |
5 | 110042311444022322010 |
6 | 1044511020405555233 |
7 | 33152015164621320 |
oct | 3213312513540405 |
9 | 502575574645743 |
10 | 115132322464005 |
11 | 337593865a0420 |
12 | 10ab54b9a15b19 |
13 | 4c31c154491b2 |
14 | 20606113cb7b7 |
15 | d49cc8b05120 |
hex | 68b6552ec105 |
115132322464005 has 64 divisors (see below), whose sum is σ = 229671195844608. Its totient is φ = 47846232092160.
The previous prime is 115132322463913. The next prime is 115132322464063. The reversal of 115132322464005 is 500464223231511.
It is not a de Polignac number, because 115132322464005 - 223 = 115132314075397 is a prime.
It is a Curzon number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 57654129 + ... + 59617641.
It is an arithmetic number, because the mean of its divisors is an integer number (3588612435072).
Almost surely, 2115132322464005 is an apocalyptic number.
115132322464005 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
115132322464005 is a deficient number, since it is larger than the sum of its proper divisors (114538873380603).
115132322464005 is a wasteful number, since it uses less digits than its factorization.
115132322464005 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2014306.
The product of its (nonzero) digits is 172800, while the sum is 39.
Adding to 115132322464005 its reverse (500464223231511), we get a palindrome (615596545695516).
The spelling of 115132322464005 in words is "one hundred fifteen trillion, one hundred thirty-two billion, three hundred twenty-two million, four hundred sixty-four thousand, five".
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