Base | Representation |
---|---|
bin | 11010001011011001010111… |
… | …000010101100101000111011 |
3 | 120002122112201200102112202012 |
4 | 122023121113002230220323 |
5 | 110042312030014131444 |
6 | 1044511023442400135 |
7 | 33152016024035156 |
oct | 3213312702545073 |
9 | 502575650375665 |
10 | 115132353661499 |
11 | 337593a2169579 |
12 | 10ab550836004b |
13 | 4c31c1ba50255 |
14 | 20606155ccc9d |
15 | d49ccb718b9e |
hex | 68b6570aca3b |
115132353661499 has 2 divisors, whose sum is σ = 115132353661500. Its totient is φ = 115132353661498.
The previous prime is 115132353661459. The next prime is 115132353661519. The reversal of 115132353661499 is 994166353231511.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 115132353661499 - 212 = 115132353657403 is a prime.
It is a super-5 number, since 5×1151323536614995 (a number of 72 digits) contains 55555 as substring.
It is not a weakly prime, because it can be changed into another prime (115132353661459) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57566176830749 + 57566176830750.
It is an arithmetic number, because the mean of its divisors is an integer number (57566176830750).
Almost surely, 2115132353661499 is an apocalyptic number.
115132353661499 is a deficient number, since it is larger than the sum of its proper divisors (1).
115132353661499 is an equidigital number, since it uses as much as digits as its factorization.
115132353661499 is an evil number, because the sum of its binary digits is even.
The product of its digits is 15746400, while the sum is 59.
The spelling of 115132353661499 in words is "one hundred fifteen trillion, one hundred thirty-two billion, three hundred fifty-three million, six hundred sixty-one thousand, four hundred ninety-nine".
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