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115132501334 = 257566250667
BaseRepresentation
bin110101100111001101…
…1101000110101010110
3102000011210010001121002
41223032123220311112
53341242410020314
6124520253023302
711214043054124
oct1531633506526
9360153101532
10115132501334
1144911328354
121a391784b32
13ab1a93b946
145802ad6914
152edc9c3ade
hex1ace6e8d56

115132501334 has 4 divisors (see below), whose sum is σ = 172698752004. Its totient is φ = 57566250666.

The previous prime is 115132501303. The next prime is 115132501339. The reversal of 115132501334 is 433105231511.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 433105231511 = 1094693956419.

It is a junction number, because it is equal to n+sod(n) for n = 115132501297 and 115132501306.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (115132501339) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 28783125332 + ... + 28783125335.

It is an arithmetic number, because the mean of its divisors is an integer number (43174688001).

Almost surely, 2115132501334 is an apocalyptic number.

115132501334 is a deficient number, since it is larger than the sum of its proper divisors (57566250670).

115132501334 is an equidigital number, since it uses as much as digits as its factorization.

115132501334 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 57566250669.

The product of its (nonzero) digits is 5400, while the sum is 29.

Adding to 115132501334 its reverse (433105231511), we get a palindrome (548237732845).

The spelling of 115132501334 in words is "one hundred fifteen billion, one hundred thirty-two million, five hundred one thousand, three hundred thirty-four".

Divisors: 1 2 57566250667 115132501334