Base | Representation |
---|---|
bin | 1010011110001010011111… |
… | …1100101001001001100111 |
3 | 1111202122220202200212101102 |
4 | 2213202213330221021213 |
5 | 3002113244442424133 |
6 | 40253052323550315 |
7 | 2265545023445354 |
oct | 247424774511147 |
9 | 44678822625342 |
10 | 11513330045543 |
11 | 3739859727977 |
12 | 135b43ab2b39b |
13 | 656919131231 |
14 | 2bb368cb962b |
15 | 14e74c6d57e8 |
hex | a78a7f29267 |
11513330045543 has 4 divisors (see below), whose sum is σ = 11513375309928. Its totient is φ = 11513284781160.
The previous prime is 11513330045533. The next prime is 11513330045551. The reversal of 11513330045543 is 34554003331511.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 11513330045543 - 222 = 11513325851239 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 11513330045497 and 11513330045506.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11513330045533) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 22248488 + ... + 22760093.
It is an arithmetic number, because the mean of its divisors is an integer number (2878343827482).
Almost surely, 211513330045543 is an apocalyptic number.
11513330045543 is a deficient number, since it is larger than the sum of its proper divisors (45264385).
11513330045543 is an equidigital number, since it uses as much as digits as its factorization.
11513330045543 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 45264384.
The product of its (nonzero) digits is 162000, while the sum is 38.
The spelling of 11513330045543 in words is "eleven trillion, five hundred thirteen billion, three hundred thirty million, forty-five thousand, five hundred forty-three".
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