Search a number
-
+
1151341483 is a prime number
BaseRepresentation
bin100010010100000…
…0001001110101011
32222020110012121011
41010220001032223
54324220411413
6310125124351
740350145465
oct10450011653
92866405534
101151341483
115409a1996
122816b96b7
131546b8866
14acca5135
156b12833d
hex44a013ab

1151341483 has 2 divisors, whose sum is σ = 1151341484. Its totient is φ = 1151341482.

The previous prime is 1151341447. The next prime is 1151341523. The reversal of 1151341483 is 3841431511.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1151341483 is a prime.

It is not a weakly prime, because it can be changed into another prime (1151341283) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 575670741 + 575670742.

It is an arithmetic number, because the mean of its divisors is an integer number (575670742).

Almost surely, 21151341483 is an apocalyptic number.

1151341483 is a deficient number, since it is larger than the sum of its proper divisors (1).

1151341483 is an equidigital number, since it uses as much as digits as its factorization.

1151341483 is an evil number, because the sum of its binary digits is even.

The product of its digits is 5760, while the sum is 31.

The square root of 1151341483 is about 33931.4232386441. The cubic root of 1151341483 is about 1048.0967739214.

Adding to 1151341483 its reverse (3841431511), we get a palindrome (4992772994).

The spelling of 1151341483 in words is "one billion, one hundred fifty-one million, three hundred forty-one thousand, four hundred eighty-three".