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115134633060361 is a prime number
BaseRepresentation
bin11010001011011011011110…
…111001111010100000001001
3120002122202121112112000011021
4122023123132321322200021
5110042331212030412421
61044512041550032441
733152126352434665
oct3213333671724011
9502582545460137
10115134633060361
113375a361899692
1210ab5a437a8721
134c321c3061485
1420607902178a5
15d49db18bb341
hex68b6dee7a809

115134633060361 has 2 divisors, whose sum is σ = 115134633060362. Its totient is φ = 115134633060360.

The previous prime is 115134633060287. The next prime is 115134633060467. The reversal of 115134633060361 is 163060336431511.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 62805323850361 + 52329309210000 = 7924981^2 + 7233900^2 .

It is an emirp because it is prime and its reverse (163060336431511) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 115134633060361 - 235 = 115100273321993 is a prime.

It is not a weakly prime, because it can be changed into another prime (115134633760361) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57567316530180 + 57567316530181.

It is an arithmetic number, because the mean of its divisors is an integer number (57567316530181).

Almost surely, 2115134633060361 is an apocalyptic number.

It is an amenable number.

115134633060361 is a deficient number, since it is larger than the sum of its proper divisors (1).

115134633060361 is an equidigital number, since it uses as much as digits as its factorization.

115134633060361 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 349920, while the sum is 43.

Adding to 115134633060361 its reverse (163060336431511), we get a palindrome (278194969491872).

The spelling of 115134633060361 in words is "one hundred fifteen trillion, one hundred thirty-four billion, six hundred thirty-three million, sixty thousand, three hundred sixty-one".