115135405120141 has 6 divisors (see below), whose sum is σ = 133933022282670. Its totient is φ = 98687490102936.

The previous prime is 115135405120133. The next prime is 115135405120189. The reversal of 115135405120141 is 141021504531511.

It can be written as a sum of positive squares in only one way, i.e., 97592467632100 + 17542937488041 = 9878890^2 + 4188429^2 .

It is not a de Polignac number, because 115135405120141 - 2³ = 115135405120133 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 115135405120097 and 115135405120106.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (115135405124141) by changing a digit.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 1174851072606 + ... + 1174851072703.

It is an arithmetic number, because the mean of its divisors is an integer number (22322170380445).

Almost surely, 2^{115135405120141} is an apocalyptic number.

It is an amenable number.

115135405120141 is a deficient number, since it is larger than the sum of its proper divisors (18797617162529).

115135405120141 is an equidigital number, since it uses as much as digits as its factorization.

115135405120141 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2349702145323 (or 2349702145316 counting only the distinct ones).

The product of its (nonzero) digits is 12000, while the sum is 34.

Adding to 115135405120141 its reverse (141021504531511), we get a palindrome (256156909651652).

The spelling of 115135405120141 in words is "one hundred fifteen trillion, one hundred thirty-five billion, four hundred five million, one hundred twenty thousand, one hundred forty-one".