11514104431425 has 30 divisors (see below), whose sum is σ = 21328101594998. Its totient is φ = 6140855695680.

The previous prime is 11514104431399. The next prime is 11514104431433. The reversal of 11514104431425 is 52413440141511.

11514104431425 is a `hidden beast` number, since 1 + 1 + 514 + 104 + 4 + 3 + 14 + 25 = 666.

It can be written as a sum of positive squares in 3 ways, for example, as 3782495978496 + 7731608452929 = 1944864^2 + 2780577^2 .

It is not a de Polignac number, because 11514104431425 - 2⁵ = 11514104431393 is a prime.

It is a super-3 number, since 3×11514104431425³ (a number of 40 digits) contains 333 as substring.

It is a Duffinian number.

It is a Curzon number.

It is a self number, because there is not a number n which added to its sum of digits gives 11514104431425.

It is an unprimeable number.

It is a polite number, since it can be written in 29 ways as a sum of consecutive naturals, for example, 2842986724 + ... + 2842990773.

Almost surely, 2^{11514104431425} is an apocalyptic number.

11514104431425 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

It is an amenable number.

11514104431425 is a deficient number, since it is larger than the sum of its proper divisors (9813997163573).

11514104431425 is an equidigital number, since it uses as much as digits as its factorization.

11514104431425 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5685977519 (or 5685977505 counting only the distinct ones).

The product of its (nonzero) digits is 38400, while the sum is 36.

Adding to 11514104431425 its reverse (52413440141511), we get a palindrome (63927544572936).

The spelling of 11514104431425 in words is "eleven trillion, five hundred fourteen billion, one hundred four million, four hundred thirty-one thousand, four hundred twenty-five".