1151412113 has 2 divisors, whose sum is σ = 1151412114. Its totient is φ = 1151412112.

The previous prime is 1151412107. The next prime is 1151412151. The reversal of 1151412113 is 3112141511.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 890007889 + 261404224 = 29833^2 + 16168^2 .

It is an emirp because it is prime and its reverse (3112141511) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1151412113 is a prime.

It is not a weakly prime, because it can be changed into another prime (1151411113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 575706056 + 575706057.

It is an arithmetic number, because the mean of its divisors is an integer number (575706057).

Almost surely, 2^1151412113 is an apocalyptic number.

It is an amenable number.

1151412113 is a deficient number, since it is larger than the sum of its proper divisors (1).

1151412113 is an equidigital number, since it uses as much as digits as its factorization.

1151412113 is an evil number, because the sum of its binary digits is even.

The product of its digits is 120, while the sum is 20.

The square root of 1151412113 is about 33932.4639983600. The cubic root of 1151412113 is about 1048.1182056057.

Adding to 1151412113 its reverse (3112141511), we get a palindrome (4263553624).

The spelling of 1151412113 in words is "one billion, one hundred fifty-one million, four hundred twelve thousand, one hundred thirteen".