Base | Representation |
---|---|
bin | 1010011110001101100110… |
… | …1010011000111100111011 |
3 | 1111202202001220011022100221 |
4 | 2213203121222120330323 |
5 | 3002122002003341103 |
6 | 40253311201040511 |
7 | 2265604502124406 |
oct | 247433152307473 |
9 | 44682056138327 |
10 | 11514164121403 |
11 | 373a147522469 |
12 | 135b632326137 |
13 | 656a1cb85348 |
14 | 2bb407994d3d |
15 | 14e79aa3e1bd |
hex | a78d9a98f3b |
11514164121403 has 4 divisors (see below), whose sum is σ = 11759146336800. Its totient is φ = 11269181906008.
The previous prime is 11514164121401. The next prime is 11514164121407. The reversal of 11514164121403 is 30412146141511.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 11514164121403 - 21 = 11514164121401 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (11514164121401) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 122491107628 + ... + 122491107721.
It is an arithmetic number, because the mean of its divisors is an integer number (2939786584200).
Almost surely, 211514164121403 is an apocalyptic number.
11514164121403 is a deficient number, since it is larger than the sum of its proper divisors (244982215397).
11514164121403 is an equidigital number, since it uses as much as digits as its factorization.
11514164121403 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 244982215396.
The product of its (nonzero) digits is 11520, while the sum is 34.
The spelling of 11514164121403 in words is "eleven trillion, five hundred fourteen billion, one hundred sixty-four million, one hundred twenty-one thousand, four hundred three".
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