Base | Representation |
---|---|
bin | 10101011100100110… |
… | …10110001001100001 |
3 | 1002201110002002010211 |
4 | 22232103112021201 |
5 | 142040121213013 |
6 | 5142314054121 |
7 | 555222303406 |
oct | 125623261141 |
9 | 32643062124 |
10 | 11514241633 |
11 | 4979542184 |
12 | 229411a341 |
13 | 1116627b3b |
14 | 7b32d22ad |
15 | 475cbc23d |
hex | 2ae4d6261 |
11514241633 has 2 divisors, whose sum is σ = 11514241634. Its totient is φ = 11514241632.
The previous prime is 11514241567. The next prime is 11514241637. The reversal of 11514241633 is 33614241511.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 8625394129 + 2888847504 = 92873^2 + 53748^2 .
It is a cyclic number.
It is not a de Polignac number, because 11514241633 - 233 = 2924307041 is a prime.
It is a super-2 number, since 2×115142416332 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 11514241595 and 11514241604.
It is not a weakly prime, because it can be changed into another prime (11514241637) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5757120816 + 5757120817.
It is an arithmetic number, because the mean of its divisors is an integer number (5757120817).
Almost surely, 211514241633 is an apocalyptic number.
It is an amenable number.
11514241633 is a deficient number, since it is larger than the sum of its proper divisors (1).
11514241633 is an equidigital number, since it uses as much as digits as its factorization.
11514241633 is an evil number, because the sum of its binary digits is even.
The product of its digits is 8640, while the sum is 31.
The spelling of 11514241633 in words is "eleven billion, five hundred fourteen million, two hundred forty-one thousand, six hundred thirty-three".
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