11514654056031 has 12 divisors (see below), whose sum is σ = 17859463434072. Its totient is φ = 6579802317648.

The previous prime is 11514654055979. The next prime is 11514654056041. The reversal of 11514654056031 is 13065045641511.

It is a happy number.

It is not a de Polignac number, because 11514654056031 - 2²¹ = 11514651958879 is a prime.

It is a super-3 number, since 3×11514654056031³ (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11514654056041) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 39165489840 + ... + 39165490133.

It is an arithmetic number, because the mean of its divisors is an integer number (1488288619506).

Almost surely, 2^{11514654056031} is an apocalyptic number.

11514654056031 is a deficient number, since it is larger than the sum of its proper divisors (6344809378041).

11514654056031 is an equidigital number, since it uses as much as digits as its factorization.

11514654056031 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 78330979990 (or 78330979983 counting only the distinct ones).

The product of its (nonzero) digits is 216000, while the sum is 42.

Adding to 11514654056031 its reverse (13065045641511), we get a palindrome (24579699697542).

The spelling of 11514654056031 in words is "eleven trillion, five hundred fourteen billion, six hundred fifty-four million, fifty-six thousand, thirty-one".