Search a number
-
+
115150032453 = 371540610481
BaseRepresentation
bin110101100111101111…
…0100000111001000101
3102000020000002201202210
41223033132200321011
53341311402014303
6124522120454033
711214345061221
oct1531736407105
9360200081683
10115150032453
1144920211785
121a39761a319
13ab214693a1
14580517b781
152ede2d8203
hex1acf7a0e45

115150032453 has 8 divisors (see below), whose sum is σ = 155695818816. Its totient is φ = 75685467200.

The previous prime is 115150032377. The next prime is 115150032523. The reversal of 115150032453 is 354230051511.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 115150032453 - 213 = 115150024261 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 115150032453.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (115150032353) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 270305028 + ... + 270305453.

It is an arithmetic number, because the mean of its divisors is an integer number (19461977352).

Almost surely, 2115150032453 is an apocalyptic number.

It is an amenable number.

115150032453 is a deficient number, since it is larger than the sum of its proper divisors (40545786363).

115150032453 is an equidigital number, since it uses as much as digits as its factorization.

115150032453 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 540610555.

The product of its (nonzero) digits is 9000, while the sum is 30.

Adding to 115150032453 its reverse (354230051511), we get a palindrome (469380083964).

The spelling of 115150032453 in words is "one hundred fifteen billion, one hundred fifty million, thirty-two thousand, four hundred fifty-three".

Divisors: 1 3 71 213 540610481 1621831443 38383344151 115150032453