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11515011106913 is a prime number
BaseRepresentation
bin1010011110010000110000…
…1001011000100001100001
31111202211020220220122001122
42213210030021120201201
53002130220320410123
640253531214542025
72265634465312046
oct247441411304141
944684226818048
1011515011106913
11373a541635196
12135b829b07915
13656b264a94c2
142bb4882711cd
1514e7ea097bc8
hexa790c258861

11515011106913 has 2 divisors, whose sum is σ = 11515011106914. Its totient is φ = 11515011106912.

The previous prime is 11515011106903. The next prime is 11515011106979. The reversal of 11515011106913 is 31960111051511.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 9791942707264 + 1723068399649 = 3129208^2 + 1312657^2 .

It is an emirp because it is prime and its reverse (31960111051511) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11515011106913 - 226 = 11514943998049 is a prime.

It is not a weakly prime, because it can be changed into another prime (11515011106903) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5757505553456 + 5757505553457.

It is an arithmetic number, because the mean of its divisors is an integer number (5757505553457).

Almost surely, 211515011106913 is an apocalyptic number.

It is an amenable number.

11515011106913 is a deficient number, since it is larger than the sum of its proper divisors (1).

11515011106913 is an equidigital number, since it uses as much as digits as its factorization.

11515011106913 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4050, while the sum is 35.

The spelling of 11515011106913 in words is "eleven trillion, five hundred fifteen billion, eleven million, one hundred six thousand, nine hundred thirteen".