Base | Representation |
---|---|
bin | 10000110000011011100… |
… | …011111100110011010011 |
3 | 11002002020222002000220111 |
4 | 100300123203330303103 |
5 | 122331244443103433 |
6 | 2240555325422151 |
7 | 146123403323164 |
oct | 20603343746323 |
9 | 4062228060814 |
10 | 1151513644243 |
11 | 4043994833a6 |
12 | 16720770a957 |
13 | 84783306781 |
14 | 3da3ac4d76b |
15 | 1ee48187dcd |
hex | 10c1b8fccd3 |
1151513644243 has 2 divisors, whose sum is σ = 1151513644244. Its totient is φ = 1151513644242.
The previous prime is 1151513644219. The next prime is 1151513644271. The reversal of 1151513644243 is 3424463151511.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1151513644243 - 213 = 1151513636051 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1151513644196 and 1151513644205.
It is not a weakly prime, because it can be changed into another prime (1151513644273) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 575756822121 + 575756822122.
It is an arithmetic number, because the mean of its divisors is an integer number (575756822122).
Almost surely, 21151513644243 is an apocalyptic number.
1151513644243 is a deficient number, since it is larger than the sum of its proper divisors (1).
1151513644243 is an equidigital number, since it uses as much as digits as its factorization.
1151513644243 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 172800, while the sum is 40.
Adding to 1151513644243 its reverse (3424463151511), we get a palindrome (4575976795754).
The spelling of 1151513644243 in words is "one trillion, one hundred fifty-one billion, five hundred thirteen million, six hundred forty-four thousand, two hundred forty-three".
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