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11515151214121 is a prime number
BaseRepresentation
bin1010011110010001010001…
…1111110110011000101001
31111202211121200112211000111
42213210110133312120221
53002131012202322441
640253553141534321
72265641116226632
oct247442437663051
944684550484014
1011515151214121
11373a60372a875
12135b868a143a1
13656b49523589
142bb49cb02889
1514e807521081
hexa79147f6629

11515151214121 has 2 divisors, whose sum is σ = 11515151214122. Its totient is φ = 11515151214120.

The previous prime is 11515151214101. The next prime is 11515151214187. The reversal of 11515151214121 is 12141215151511.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 11217977955625 + 297173258496 = 3349325^2 + 545136^2 .

It is a cyclic number.

It is not a de Polignac number, because 11515151214121 - 221 = 11515149116969 is a prime.

It is not a weakly prime, because it can be changed into another prime (11515151214101) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5757575607060 + 5757575607061.

It is an arithmetic number, because the mean of its divisors is an integer number (5757575607061).

Almost surely, 211515151214121 is an apocalyptic number.

It is an amenable number.

11515151214121 is a deficient number, since it is larger than the sum of its proper divisors (1).

11515151214121 is an equidigital number, since it uses as much as digits as its factorization.

11515151214121 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 2000, while the sum is 31.

Adding to 11515151214121 its reverse (12141215151511), we get a palindrome (23656366365632).

The spelling of 11515151214121 in words is "eleven trillion, five hundred fifteen billion, one hundred fifty-one million, two hundred fourteen thousand, one hundred twenty-one".