Base | Representation |
---|---|
bin | 11010001011101011110000… |
… | …110100001111011000100111 |
3 | 120002201102201202220220012220 |
4 | 122023223300310033120213 |
5 | 110043123012014311403 |
6 | 1044524052311043423 |
7 | 33153315501232626 |
oct | 3213536064173047 |
9 | 502642652826186 |
10 | 115152113432103 |
11 | 33766812028700 |
12 | 10ab9301970573 |
13 | 4c33a4a7267c7 |
14 | 206156ba1d6bd |
15 | d4a586330953 |
hex | 68baf0d0f627 |
115152113432103 has 48 divisors (see below), whose sum is σ = 169189980960000. Its totient is φ = 69612728169600.
The previous prime is 115152113432093. The next prime is 115152113432141. The reversal of 115152113432103 is 301234311251511.
It is not a de Polignac number, because 115152113432103 - 214 = 115152113415719 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (33).
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (115152113432173) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 266959398 + ... + 267390396.
It is an arithmetic number, because the mean of its divisors is an integer number (3524791270000).
Almost surely, 2115152113432103 is an apocalyptic number.
115152113432103 is a deficient number, since it is larger than the sum of its proper divisors (54037867527897).
115152113432103 is a wasteful number, since it uses less digits than its factorization.
115152113432103 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 432884 (or 432873 counting only the distinct ones).
The product of its (nonzero) digits is 10800, while the sum is 33.
Adding to 115152113432103 its reverse (301234311251511), we get a palindrome (416386424683614).
The spelling of 115152113432103 in words is "one hundred fifteen trillion, one hundred fifty-two billion, one hundred thirteen million, four hundred thirty-two thousand, one hundred three".
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