| Base | Representation |
|---|---|
| bin | 11010001011101011111101… |
| … | …110110011001010110111010 |
| 3 | 120002201110022000101102121210 |
| 4 | 122023223331312121112322 |
| 5 | 110043123434004213200 |
| 6 | 1044524130121543550 |
| 7 | 33153324065003466 |
| oct | 3213537566312672 |
| 9 | 502643260342553 |
| 10 | 115152332101050 |
| 11 | 33766914501942 |
| 12 | 10ab9363044bb6 |
| 13 | 4c33a83b1940a |
| 14 | 206158caa14a6 |
| 15 | d4a59a626650 |
| hex | 68bafdd995ba |
115152332101050 has 192 divisors, whose sum is σ = 311158053360000. Its totient is φ = 28071348802560.
The previous prime is 115152332101049. The next prime is 115152332101063. The reversal of 115152332101050 is 50101233251511.
It is a super-2 number, since 2×1151523321010502 (a number of 29 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (30).
It is a junction number, because it is equal to n+sod(n) for n = 115152332100999 and 115152332101017.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 139514976 + ... + 140337924.
It is an arithmetic number, because the mean of its divisors is an integer number (1620614861250).
Almost surely, 2115152332101050 is an apocalyptic number.
115152332101050 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is a practical number, because each smaller number is the sum of distinct divisors of 115152332101050, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (155579026680000).
115152332101050 is an abundant number, since it is smaller than the sum of its proper divisors (196005721258950).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
115152332101050 is a wasteful number, since it uses less digits than its factorization.
115152332101050 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 824705 (or 824700 counting only the distinct ones).
The product of its (nonzero) digits is 4500, while the sum is 30.
Adding to 115152332101050 its reverse (50101233251511), we get a palindrome (165253565352561).
The spelling of 115152332101050 in words is "one hundred fifteen trillion, one hundred fifty-two billion, three hundred thirty-two million, one hundred one thousand, fifty".
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