Base | Representation |
---|---|
bin | 11010001011101100111001… |
… | …011101100001000110011001 |
3 | 120002201112212201021100002120 |
4 | 122023230321131201012121 |
5 | 110043133011021241441 |
6 | 1044524413245451453 |
7 | 33153360630546300 |
oct | 3213547135410631 |
9 | 502645781240076 |
10 | 115153332212121 |
11 | 33767287aa1115 |
12 | 10ab95a1b70b89 |
13 | 4c33bb3095008 |
14 | 206164583b437 |
15 | d4a60832a966 |
hex | 68bb39761199 |
115153332212121 has 24 divisors (see below), whose sum is σ = 181533121922304. Its totient is φ = 64723184376480.
The previous prime is 115153332212119. The next prime is 115153332212143. The reversal of 115153332212121 is 121212233351511.
It is not a de Polignac number, because 115153332212121 - 21 = 115153332212119 is a prime.
It is not an unprimeable number, because it can be changed into a prime (115153332212101) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 6420941865 + ... + 6420959798.
It is an arithmetic number, because the mean of its divisors is an integer number (7563880080096).
Almost surely, 2115153332212121 is an apocalyptic number.
It is an amenable number.
115153332212121 is a deficient number, since it is larger than the sum of its proper divisors (66379789710183).
115153332212121 is a wasteful number, since it uses less digits than its factorization.
115153332212121 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 12841901741 (or 12841901734 counting only the distinct ones).
The product of its digits is 10800, while the sum is 33.
Adding to 115153332212121 its reverse (121212233351511), we get a palindrome (236365565563632).
The spelling of 115153332212121 in words is "one hundred fifteen trillion, one hundred fifty-three billion, three hundred thirty-two million, two hundred twelve thousand, one hundred twenty-one".
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