115153413421253 has 4 divisors (see below), whose sum is σ = 115467182940480. Its totient is φ = 114839643902028.

The previous prime is 115153413421231. The next prime is 115153413421261. The reversal of 115153413421253 is 352124314351511.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-115153413421253 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a self number, because there is not a number n which added to its sum of digits gives 115153413421253.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (115153413421223) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 156884759063 + ... + 156884759796.

It is an arithmetic number, because the mean of its divisors is an integer number (28866795735120).

Almost surely, 2^{115153413421253} is an apocalyptic number.

It is an amenable number.

115153413421253 is a deficient number, since it is larger than the sum of its proper divisors (313769519227).

115153413421253 is an equidigital number, since it uses as much as digits as its factorization.

115153413421253 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 313769519226.

The product of its digits is 216000, while the sum is 41.

Adding to 115153413421253 its reverse (352124314351511), we get a palindrome (467277727772764).

The spelling of 115153413421253 in words is "one hundred fifteen trillion, one hundred fifty-three billion, four hundred thirteen million, four hundred twenty-one thousand, two hundred fifty-three".