Base | Representation |
---|---|
bin | 11010001011101100111110… |
… | …010011010011100010101111 |
3 | 120002201120002101002012001101 |
4 | 122023230332103103202233 |
5 | 110043133142313434411 |
6 | 1044524425310223531 |
7 | 33153362635036453 |
oct | 3213547623234257 |
9 | 502646071065041 |
10 | 115153413421231 |
11 | 33767319918789 |
12 | 10ab96051b4ba7 |
13 | 4c33bc6b59843 |
14 | 206165253a663 |
15 | d4a61051c8c1 |
hex | 68bb3e4d38af |
115153413421231 has 2 divisors, whose sum is σ = 115153413421232. Its totient is φ = 115153413421230.
The previous prime is 115153413421223. The next prime is 115153413421261. The reversal of 115153413421231 is 132124314351511.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 115153413421231 - 23 = 115153413421223 is a prime.
It is a super-2 number, since 2×1151534134212312 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (115153413421261) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57576706710615 + 57576706710616.
It is an arithmetic number, because the mean of its divisors is an integer number (57576706710616).
Almost surely, 2115153413421231 is an apocalyptic number.
115153413421231 is a deficient number, since it is larger than the sum of its proper divisors (1).
115153413421231 is an equidigital number, since it uses as much as digits as its factorization.
115153413421231 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 43200, while the sum is 37.
Adding to 115153413421231 its reverse (132124314351511), we get a palindrome (247277727772742).
The spelling of 115153413421231 in words is "one hundred fifteen trillion, one hundred fifty-three billion, four hundred thirteen million, four hundred twenty-one thousand, two hundred thirty-one".
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