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115153414038017 is a prime number
BaseRepresentation
bin11010001011101100111110…
…010101101010001000000001
3120002201120002102020112010022
4122023230332111222020001
5110043133142443204032
61044524425331343225
733153362643215615
oct3213547625521001
9502646072215108
10115153414038017
113376731a1aa123
1210ab9605451b15
134c33bc70144c4
14206165265b345
15d4a6105e0512
hex68bb3e56a201

115153414038017 has 2 divisors, whose sum is σ = 115153414038018. Its totient is φ = 115153414038016.

The previous prime is 115153414038007. The next prime is 115153414038031. The reversal of 115153414038017 is 710830414351511.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 114568251766336 + 585162271681 = 10703656^2 + 764959^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-115153414038017 is a prime.

It is a super-2 number, since 2×1151534140380172 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (115153414038007) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57576707019008 + 57576707019009.

It is an arithmetic number, because the mean of its divisors is an integer number (57576707019009).

Almost surely, 2115153414038017 is an apocalyptic number.

It is an amenable number.

115153414038017 is a deficient number, since it is larger than the sum of its proper divisors (1).

115153414038017 is an equidigital number, since it uses as much as digits as its factorization.

115153414038017 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 201600, while the sum is 44.

Adding to 115153414038017 its reverse (710830414351511), we get a palindrome (825983828389528).

The spelling of 115153414038017 in words is "one hundred fifteen trillion, one hundred fifty-three billion, four hundred fourteen million, thirty-eight thousand, seventeen".