Base | Representation |
---|---|
bin | 11010001011101100111110… |
… | …010101101111010110001001 |
3 | 120002201120002102021121110022 |
4 | 122023230332111233112021 |
5 | 110043133142444400101 |
6 | 1044524425332030225 |
7 | 33153362643335144 |
oct | 3213547625572611 |
9 | 502646072247408 |
10 | 115153414059401 |
11 | 3376731a2141a3 |
12 | 10ab9605462375 |
13 | 4c33bc7021163 |
14 | 206165266505b |
15 | d4a6105e6a1b |
hex | 68bb3e56f589 |
115153414059401 has 2 divisors, whose sum is σ = 115153414059402. Its totient is φ = 115153414059400.
The previous prime is 115153414059373. The next prime is 115153414059419. The reversal of 115153414059401 is 104950414351511.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 70178753180176 + 44974660879225 = 8377276^2 + 6706315^2 .
It is a cyclic number.
It is not a de Polignac number, because 115153414059401 - 222 = 115153409865097 is a prime.
It is not a weakly prime, because it can be changed into another prime (115153414059421) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57576707029700 + 57576707029701.
It is an arithmetic number, because the mean of its divisors is an integer number (57576707029701).
Almost surely, 2115153414059401 is an apocalyptic number.
It is an amenable number.
115153414059401 is a deficient number, since it is larger than the sum of its proper divisors (1).
115153414059401 is an equidigital number, since it uses as much as digits as its factorization.
115153414059401 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 216000, while the sum is 44.
The spelling of 115153414059401 in words is "one hundred fifteen trillion, one hundred fifty-three billion, four hundred fourteen million, fifty-nine thousand, four hundred one".
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