Base | Representation |
---|---|
bin | 11010001011101110110000… |
… | …001111111111001011010101 |
3 | 120002201202000121100021101221 |
4 | 122023232300033333023111 |
5 | 110043201101214412010 |
6 | 1044525343121250341 |
7 | 33153461210353423 |
oct | 3213566017771325 |
9 | 502652017307357 |
10 | 115155325154005 |
11 | 3376810aa57924 |
12 | 10ab9a594939b1 |
13 | 4c3413cc3a876 |
14 | 20617943ba113 |
15 | d4a6c3296dda |
hex | 68bbb03ff2d5 |
115155325154005 has 16 divisors (see below), whose sum is σ = 141403617432000. Its totient is φ = 89979550754688.
The previous prime is 115155325153907. The next prime is 115155325154047. The reversal of 115155325154005 is 500451523551511.
It is a cyclic number.
It is not a de Polignac number, because 115155325154005 - 237 = 115017886200533 is a prime.
It is a super-2 number, since 2×1151553251540052 (a number of 29 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (43).
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1712289 + ... + 15272281.
It is an arithmetic number, because the mean of its divisors is an integer number (8837726089500).
Almost surely, 2115155325154005 is an apocalyptic number.
It is an amenable number.
115155325154005 is a deficient number, since it is larger than the sum of its proper divisors (26248292277995).
115155325154005 is a wasteful number, since it uses less digits than its factorization.
115155325154005 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 13599540.
The product of its (nonzero) digits is 375000, while the sum is 43.
The spelling of 115155325154005 in words is "one hundred fifteen trillion, one hundred fifty-five billion, three hundred twenty-five million, one hundred fifty-four thousand, five".
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