Base | Representation |
---|---|
bin | 11010001011101110110000… |
… | …001111111111001001110011 |
3 | 120002201202000121100021021022 |
4 | 122023232300033333021303 |
5 | 110043201101214411112 |
6 | 1044525343121250055 |
7 | 33153461210353223 |
oct | 3213566017771163 |
9 | 502652017307238 |
10 | 115155325153907 |
11 | 3376810aa57845 |
12 | 10ab9a5949392b |
13 | 4c3413cc3a7cc |
14 | 20617943ba083 |
15 | d4a6c3296d72 |
hex | 68bbb03ff273 |
115155325153907 has 2 divisors, whose sum is σ = 115155325153908. Its totient is φ = 115155325153906.
The previous prime is 115155325153829. The next prime is 115155325154047. The reversal of 115155325153907 is 709351523551511.
It is a weak prime.
It is an emirp because it is prime and its reverse (709351523551511) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 115155325153907 - 222 = 115155320959603 is a prime.
It is a super-2 number, since 2×1151553251539072 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (115155325453907) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57577662576953 + 57577662576954.
It is an arithmetic number, because the mean of its divisors is an integer number (57577662576954).
Almost surely, 2115155325153907 is an apocalyptic number.
115155325153907 is a deficient number, since it is larger than the sum of its proper divisors (1).
115155325153907 is an equidigital number, since it uses as much as digits as its factorization.
115155325153907 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3543750, while the sum is 53.
The spelling of 115155325153907 in words is "one hundred fifteen trillion, one hundred fifty-five billion, three hundred twenty-five million, one hundred fifty-three thousand, nine hundred seven".
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