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115155325153907 is a prime number
BaseRepresentation
bin11010001011101110110000…
…001111111111001001110011
3120002201202000121100021021022
4122023232300033333021303
5110043201101214411112
61044525343121250055
733153461210353223
oct3213566017771163
9502652017307238
10115155325153907
113376810aa57845
1210ab9a5949392b
134c3413cc3a7cc
1420617943ba083
15d4a6c3296d72
hex68bbb03ff273

115155325153907 has 2 divisors, whose sum is σ = 115155325153908. Its totient is φ = 115155325153906.

The previous prime is 115155325153829. The next prime is 115155325154047. The reversal of 115155325153907 is 709351523551511.

It is a weak prime.

It is an emirp because it is prime and its reverse (709351523551511) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 115155325153907 - 222 = 115155320959603 is a prime.

It is a super-2 number, since 2×1151553251539072 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (115155325453907) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57577662576953 + 57577662576954.

It is an arithmetic number, because the mean of its divisors is an integer number (57577662576954).

Almost surely, 2115155325153907 is an apocalyptic number.

115155325153907 is a deficient number, since it is larger than the sum of its proper divisors (1).

115155325153907 is an equidigital number, since it uses as much as digits as its factorization.

115155325153907 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3543750, while the sum is 53.

The spelling of 115155325153907 in words is "one hundred fifteen trillion, one hundred fifty-five billion, three hundred twenty-five million, one hundred fifty-three thousand, nine hundred seven".