Base | Representation |
---|---|
bin | 10101011100110100… |
… | …11100010111000011 |
3 | 1002201120120121012101 |
4 | 22232122130113003 |
5 | 142041110231313 |
6 | 5142422011231 |
7 | 555244152433 |
oct | 125632342703 |
9 | 32646517171 |
10 | 11516102083 |
11 | 497a5a2a42 |
12 | 2294876b17 |
13 | 1116b298b5 |
14 | 7b36582c3 |
15 | 4760385dd |
hex | 2ae69c5c3 |
11516102083 has 2 divisors, whose sum is σ = 11516102084. Its totient is φ = 11516102082.
The previous prime is 11516102071. The next prime is 11516102119. The reversal of 11516102083 is 38020161511.
It is a weak prime.
It is an emirp because it is prime and its reverse (38020161511) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11516102083 - 217 = 11515971011 is a prime.
It is not a weakly prime, because it can be changed into another prime (11516102383) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5758051041 + 5758051042.
It is an arithmetic number, because the mean of its divisors is an integer number (5758051042).
Almost surely, 211516102083 is an apocalyptic number.
11516102083 is a deficient number, since it is larger than the sum of its proper divisors (1).
11516102083 is an equidigital number, since it uses as much as digits as its factorization.
11516102083 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1440, while the sum is 28.
Adding to 11516102083 its reverse (38020161511), we get a palindrome (49536263594).
The spelling of 11516102083 in words is "eleven billion, five hundred sixteen million, one hundred two thousand, eighty-three".
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