115200103 has 4 divisors (see below), whose sum is σ = 115452640. Its totient is φ = 114947568.

The previous prime is 115200101. The next prime is 115200121. The reversal of 115200103 is 301002511.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 301002511 = 37 ⋅8135203.

It is a cyclic number.

It is not a de Polignac number, because 115200103 - 2¹ = 115200101 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (115200101) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 125583 + ... + 126496.

It is an arithmetic number, because the mean of its divisors is an integer number (28863160).

Almost surely, 2^115200103 is an apocalyptic number.

115200103 is a deficient number, since it is larger than the sum of its proper divisors (252537).

115200103 is an equidigital number, since it uses as much as digits as its factorization.

115200103 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 252536.

The product of its (nonzero) digits is 30, while the sum is 13.

The square root of 115200103 is about 10733.1310902271. The cubic root of 115200103 is about 486.5763046613.

Adding to 115200103 its reverse (301002511), we get a palindrome (416202614).

The spelling of 115200103 in words is "one hundred fifteen million, two hundred thousand, one hundred three".