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1152003020143 = 1282878979889
BaseRepresentation
bin10000110000111000101…
…110110001010101101111
311002010112001220220102211
4100300320232301111233
5122333300233121033
62241120050431251
7146141465051113
oct20607056612557
94063461826384
101152003020143
1140461a743798
12167323592527
138483080bc01
143da85c3b743
151ee761032cd
hex10c38bb156f

1152003020143 has 4 divisors (see below), whose sum is σ = 1152012128320. Its totient is φ = 1151993911968.

The previous prime is 1152003020131. The next prime is 1152003020171. The reversal of 1152003020143 is 3410203002511.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1152003020143 - 221 = 1152000922991 is a prime.

It is a super-2 number, since 2×11520030201432 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1152003020543) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4361658 + ... + 4618231.

It is an arithmetic number, because the mean of its divisors is an integer number (288003032080).

Almost surely, 21152003020143 is an apocalyptic number.

1152003020143 is a deficient number, since it is larger than the sum of its proper divisors (9108177).

1152003020143 is an equidigital number, since it uses as much as digits as its factorization.

1152003020143 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 9108176.

The product of its (nonzero) digits is 720, while the sum is 22.

Adding to 1152003020143 its reverse (3410203002511), we get a palindrome (4562206022654).

The spelling of 1152003020143 in words is "one trillion, one hundred fifty-two billion, three million, twenty thousand, one hundred forty-three".

Divisors: 1 128287 8979889 1152003020143