1152004553333 has 4 divisors (see below), whose sum is σ = 1152013527948. Its totient is φ = 1151995578720.

The previous prime is 1152004553309. The next prime is 1152004553341. The reversal of 1152004553333 is 3333554002511.

It is a happy number.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 153490001284 + 998514552049 = 391778^2 + 999257^2 .

It is a cyclic number.

It is not a de Polignac number, because 1152004553333 - 2¹² = 1152004549237 is a prime.

It is a super-2 number, since 2×1152004553333² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1152004553293 and 1152004553302.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1152004553303) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4291928 + ... + 4552433.

It is an arithmetic number, because the mean of its divisors is an integer number (288003381987).

Almost surely, 2^{1152004553333} is an apocalyptic number.

It is an amenable number.

1152004553333 is a deficient number, since it is larger than the sum of its proper divisors (8974615).

1152004553333 is an equidigital number, since it uses as much as digits as its factorization.

1152004553333 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 8974614.

The product of its (nonzero) digits is 81000, while the sum is 35.

Adding to 1152004553333 its reverse (3333554002511), we get a palindrome (4485558555844).

The spelling of 1152004553333 in words is "one trillion, one hundred fifty-two billion, four million, five hundred fifty-three thousand, three hundred thirty-three".