Base | Representation |
---|---|
bin | 10101011101010101… |
… | …10110011011010001 |
3 | 1002201212200010011021 |
4 | 22232222312123101 |
5 | 142043210400103 |
6 | 5143054115441 |
7 | 555325545130 |
oct | 125652663321 |
9 | 32655603137 |
10 | 11520403153 |
11 | 4981a70446 |
12 | 22961abb81 |
13 | 11179a44cc |
14 | 7b4057917 |
15 | 4765d7bbd |
hex | 2aeab66d1 |
11520403153 has 4 divisors (see below), whose sum is σ = 13166175040. Its totient is φ = 9874631268.
The previous prime is 11520403151. The next prime is 11520403157. The reversal of 11520403153 is 35130402511.
It is a happy number.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 11520403153 - 21 = 11520403151 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (11520403151) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 822885933 + ... + 822885946.
It is an arithmetic number, because the mean of its divisors is an integer number (3291543760).
Almost surely, 211520403153 is an apocalyptic number.
It is an amenable number.
11520403153 is a deficient number, since it is larger than the sum of its proper divisors (1645771887).
11520403153 is an equidigital number, since it uses as much as digits as its factorization.
11520403153 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1645771886.
The product of its (nonzero) digits is 1800, while the sum is 25.
Adding to 11520403153 its reverse (35130402511), we get a palindrome (46650805664).
The spelling of 11520403153 in words is "eleven billion, five hundred twenty million, four hundred three thousand, one hundred fifty-three".
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