Base | Representation |
---|---|
bin | 11010001100100001111111… |
… | …101100000010110011000111 |
3 | 120002221000001000220001100211 |
4 | 122030201333230002303013 |
5 | 110100101241310001020 |
6 | 1045010522443420251 |
7 | 33160446515342200 |
oct | 3214417754026307 |
9 | 502830030801324 |
10 | 115210345000135 |
11 | 33789484252640 |
12 | 10b08653524687 |
13 | 4c3939a997538 |
14 | 20642d36965a7 |
15 | d4bd436b385a |
hex | 68c87fb02cc7 |
115210345000135 has 48 divisors (see below), whose sum is σ = 185764893795360. Its totient is φ = 67594763120640.
The previous prime is 115210345000099. The next prime is 115210345000139. The reversal of 115210345000135 is 531000543012511.
It is not a de Polignac number, because 115210345000135 - 229 = 115209808129223 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 115210345000097 and 115210345000106.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (115210345000139) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 1257297250 + ... + 1257388879.
It is an arithmetic number, because the mean of its divisors is an integer number (3870101954070).
Almost surely, 2115210345000135 is an apocalyptic number.
115210345000135 is a deficient number, since it is larger than the sum of its proper divisors (70554548795225).
115210345000135 is a wasteful number, since it uses less digits than its factorization.
115210345000135 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2514686176 (or 2514686169 counting only the distinct ones).
The product of its (nonzero) digits is 9000, while the sum is 31.
Adding to 115210345000135 its reverse (531000543012511), we get a palindrome (646210888012646).
The spelling of 115210345000135 in words is "one hundred fifteen trillion, two hundred ten billion, three hundred forty-five million, one hundred thirty-five", and thus it is an aban number.
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