Base | Representation |
---|---|
bin | 11010001100100010111111… |
… | …011010001010100001111011 |
3 | 120002221002210112111122222202 |
4 | 122030202333122022201323 |
5 | 110100110433444230120 |
6 | 1045011220513140415 |
7 | 33160515146222264 |
oct | 3214427732124173 |
9 | 502832715448882 |
10 | 115211414055035 |
11 | 33789982751391 |
12 | 10b088b155a70b |
13 | 4c3950b301cbc |
14 | 206439565b96b |
15 | d4bda7485875 |
hex | 68c8bf68a87b |
115211414055035 has 48 divisors (see below), whose sum is σ = 141345915626496. Its totient is φ = 90132407297856.
The previous prime is 115211414054941. The next prime is 115211414055041. The reversal of 115211414055035 is 530550414112511.
It is not a de Polignac number, because 115211414055035 - 224 = 115211397277819 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 115211414055035.
It is an unprimeable number.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 6515368304 + ... + 6515385986.
It is an arithmetic number, because the mean of its divisors is an integer number (2944706575552).
Almost surely, 2115211414055035 is an apocalyptic number.
115211414055035 is a deficient number, since it is larger than the sum of its proper divisors (26134501571461).
115211414055035 is an equidigital number, since it uses as much as digits as its factorization.
115211414055035 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 18720 (or 18541 counting only the distinct ones).
The product of its (nonzero) digits is 60000, while the sum is 38.
Adding to 115211414055035 its reverse (530550414112511), we get a palindrome (645761828167546).
The spelling of 115211414055035 in words is "one hundred fifteen trillion, two hundred eleven billion, four hundred fourteen million, fifty-five thousand, thirty-five".
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